SOLUTION: Find the equation of the line containing the point (3,5) and parallel to the line x+3y=9

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Question 647530: Find the equation of the line containing the point (3,5) and parallel to the line x+3y=9
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
In order to do point-slope form, we need a point and a slope. (Nice name right?)
We have a point, let's get ourselves a slope.
We are given a vital piece of information. Our line must be parallel to this one: x+3y=9. This means they must have the same slope.
If you're clever, you may know that of the form Ax+By=C, the slope is -A/B or -1/3. Otherwise, just solve for y=mx+b form and m is your slope.
3y = 9-x
y = 9/3 - x/3
y = 3 - (1/3)x
And as we predicted, our slope is -1/3.
Now we have a point and a slope.
m=-1/3
(x1,y1) = (3,5)
%28y-y1%29+=+m%2A%28x-x1%29
%28y-5%29+=+%28-1%2F3%29%28x-3%29
y-5+=+%28-1%2F3%29%2Ax+%2B+1
highlight%28y+=+%28-1%2F3%29x+%2B+6%29
Hope this helps!