SOLUTION: Find the equation of the line that passes through (5,0) and has a slope of -2/3 (Points : 5) y = -2/3x - 10/3 3y - 2x = 10 2x + 3y = 10 y = -2/3x +

Algebra ->  Linear-equations -> SOLUTION: Find the equation of the line that passes through (5,0) and has a slope of -2/3 (Points : 5) y = -2/3x - 10/3 3y - 2x = 10 2x + 3y = 10 y = -2/3x +      Log On


   

Question 639553: Find the equation of the line that passes through (5,0) and has a slope of -2/3 (Points : 5)
y = -2/3x - 10/3
3y - 2x = 10
2x + 3y = 10
y = -2/3x + 5
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
Use formula y-y0=m%28x-x0%29
Substitute x0=5, y0=0, m=-2%2F3
y-0=-%282%2F3%29%28x-5%29mulyiply by 3
3y=-2x%2B10
2x%2B3y=10
Answer: C) 2x%2B3y=10