SOLUTION: Write a slope-intercept equation of the line whose graph is described.
Perpendicular to the graph of y=1/3x+7; y-intercept (0,5)
I have been working with this for tow days n
Algebra ->
Linear-equations
-> SOLUTION: Write a slope-intercept equation of the line whose graph is described.
Perpendicular to the graph of y=1/3x+7; y-intercept (0,5)
I have been working with this for tow days n
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Question 635131: Write a slope-intercept equation of the line whose graph is described.
Perpendicular to the graph of y=1/3x+7; y-intercept (0,5)
I have been working with this for tow days now, on and off. Am I correct so far?
Perpendicular lines have slopes that multiply to -1.
m * 1/3 = -1
Hi,
Line Perpendicular to the graph of y=1/3x+7; y-intercept (0,5)
New Line with slope m.
Yes! , m = -3
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
y = -3x + 5 or in standard form: 3x-y = 5
