SOLUTION: What is the equation of the line passing through (1, 7) and parallel to the line y = –x + 5 in standard form?
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Question 630180: What is the equation of the line passing through (1, 7) and parallel to the line y = –x + 5 in standard form? Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Given
Point (x, y)=(1,7)
Line:
y=-x+5
Compare above equation with the equation of line slope-intercept form
y=mx+b
y=(-1)x+5
m=-1 and b=5
Slope of the given line m = -1 and y-intercept = b = 5
Since given line is parallel to the required line; slopes of the both line will be same.
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Now we have a point (1,7) and slope (-1) of the required line we can easily find the required line put these values in the equation of slope-intercept form to find the y-intercept of the required line
y=mx+b
7=(-1)(1)+b
7=-1+b
7+1=b
8=b
b=8
y-intercept of the required line =b=8
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Put the values of ‘m’ and ‘b’ in equation of the line slope-intercept form
y=mx+b
y=-1x+8
y=-x+8
x+y=8
Above equation is the required equation of the line in Standard form.
