SOLUTION: My question is how do you write a system of linear equations for this rectangle? If the perimeter of this rectangle is 42feet. The length is 7ft longer than the width. I am suppose

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Question 628729: My question is how do you write a system of linear equations for this rectangle? If the perimeter of this rectangle is 42feet. The length is 7ft longer than the width. I am suppose to find the deminsions, and write a system of equations and solve. Let x be length and y be the length. 2x+2y= and the second equation x=y+
Then I need the length and what the width of the rectangle is.
I would assume that I would add 42 twice, but from there I am not sure.

Answer by meetkisai(17) About Me  (Show Source):
You can put this solution on YOUR website!
You are going in the right direction, good.
Let us define x as the length of the rectangle and y as the width of the rectangle.
now,
+2x+%2B+2y+=+42 ----because this is the perimeter of the rectangle
and x = y + 7 since length is 7feet longer than the width.
Let us substitute x in the above eq which gives us,
+2%28y%2B7%29+%2B+2y+=+42
which on solving gives us,
2y+ 14 + 2y = 42 => y = 7 which is the width
and x = 14 which is the length