SOLUTION: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work.

Algebra ->  Linear-equations -> SOLUTION: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work.      Log On


   

Question 628458: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work.
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
The equation 10x - 6y = -11 in slope intercept form is y+=+%285%2F3%29x+%2B+11%2F6.
The slope of the line perpendicular to y+=+%285%2F3%29x+%2B+11%2F6 is equal to the negative reciprocal of 5%2F3 which is -3%2F5.
We want to find the equation of the line with slope -3%2F5 and containing the point (-5,-8).
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29
y+%2B+8+=+%28-3%2F5%29%28x+%2B+5%29
highlight%28y+=+%28-3%2F5%29x+-+11%29