SOLUTION: give the slope of the line defined by the equation 5x-7y+3=0

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Question 613582: give the slope of the line defined by the equation 5x-7y+3=0

Answer by radh(108) About Me  (Show Source):
You can put this solution on YOUR website!
First, let's love the 3 to the other side, to get 5x-7y=-3.

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


5x-7y=-3 Start with the given equation


5x-7y-5x=-3-5x Subtract 5x from both sides


-7y=-5x-3 Simplify


%28-7y%29%2F%28-7%29=%28-5x-3%29%2F%28-7%29 Divide both sides by -7 to isolate y


y+=+%28-5x%29%2F%28-7%29%2B%28-3%29%2F%28-7%29 Break up the fraction on the right hand side


y+=+%285%2F7%29x%2B3%2F7 Reduce and simplify


The original equation 5x-7y=-3 (standard form) is equivalent to y+=+%285%2F7%29x%2B3%2F7 (slope-intercept form)


The equation y+=+%285%2F7%29x%2B3%2F7 is in the form y=mx%2Bb where m=5%2F7 is the slope and b=3%2F7 is the y intercept.




:)