SOLUTION: rite the slope-intercept form of the equation of the line tha passes through (-2,4) and is perpendicular to the line 2x+ 3y=17

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Question 611129: rite the slope-intercept form of the equation of the line tha passes through (-2,4) and is perpendicular to the line 2x+ 3y=17
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

 



line passing through (-2,4) and perpendicular to the line:

 2x+ 3y=17 OR y = -(2/3)x + 17/3   ||slope m = (-2/3)

New Line:  m = 3/2  (negative reciprocal of (-2/3)

 y = (3/2)x + b   ||Using Pt(-2,4) to solve for b

 4 = (3/2)· (-2) + b

 7 = b

 y = (3/2)x + 7