SOLUTION: Please show me how to plug in the points for Y on these equations. I made up points for X: Thanks! equations Y = 2X - 4 (0, 3, 4) equation y = -2/3X + 4 (0, 3, 4)

Algebra ->  Linear-equations -> SOLUTION: Please show me how to plug in the points for Y on these equations. I made up points for X: Thanks! equations Y = 2X - 4 (0, 3, 4) equation y = -2/3X + 4 (0, 3, 4)       Log On


   



Question 60017: Please show me how to plug in the points for Y on these equations. I made up points for X: Thanks!
equations Y = 2X - 4 (0, 3, 4)
equation y = -2/3X + 4 (0, 3, 4)

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Please show me how to plug in the points for Y on these equations. I made up points for X:
equations Y = 2X - 4 (0, 3, 4)
equation y = -2/3X + 4 (0, 3, 4)
You don't plug in points for y if you plug in points for x, you let x = the numbers you chose and solve for y.
y=2x-4
If x=0
y=2(0)-4
y=0-4
y=-4
(0,-4) is a point on the line.
If x=3
y=2(3)-4
y=6-4
y=2
(3,2) is a point on the line.
If x=4
y=2(4)-4
y=8-4
y=4
(4,4) is a point on the line.
:
For y=%28-2%2F3%29x%2B4 Pick numbers that are divisible by 3, so that you don't have to add fractions.
for x=0
y=%28-2%2F3%29%280%29%2B4
y=0%2B4
y=4
(0,4) is a point on the line.
for x=3
y=%28-2%2F3%29%283%29%2B4
y=-6%2F3%2B4
y=-2%2B4
y=2
The point (3,2) is part of the line.
Don't choose 4, choose something like -3 for x
y=%28-2%2F3%29%28-3%29%2B4
y=6%2F3%2B4
y=2%2B4
y=6
(-3,6) is a point on the line.
Notice that both line contain the point (3,2). If you graphed these two lines on the same graph, they would cross at (3,2)
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2x-4%2C%28-2%2F3%29x%2B4%29
For fun, try to figure out which line goes to which equation.
Happy Calculating!!!