SOLUTION: how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)???
Algebra ->
Linear-equations
-> SOLUTION: how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)???
Log On
Question 59474This question is from textbook
: how would i find the equation for perpendicular lines (2 of them are intersecting), when one has the points (-1,1),(5,3), and the other (3,-2),(1,4)??? This question is from textbook
You can put this solution on YOUR website! (-1,1)(5,3) HAS THE SLOPE OF
(3-1)/(5+1)=2/6=1/3 NOW SUBSTITUTING THE 1/3 FOR THE SLOPE WE HAVE
Y=mX+b OR
Y=1/3X+b NOW REPLACING X & Y WITH ONE SET OF POINTS WE GET
1=1/3(-1)+b
1=-1/3+b
b=1-1/3
b=2/3 THUS THE EQUATION FOR THIS LINE IS
Y=1/3X+2/3
THE SECOND EQUATION HAS A SLOPE OF
(4+2)/(1-3)=6/-2=-3 THUS WE HAVE
Y=-3X+b SUBSTITUTING ONE OF THESE POINTS WE GET
3=-3*3+b
3=-9+b
b=3+9
b=12 THUS THIS LINE HAS THE EQUATION
Y=-3X+12
(