SOLUTION: would these pair of equations be parallel, perpendicular, or neither? 4x-3y=36;3x+4y=20?? how about ax-by=c;-ax+by=d??

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Question 59473This question is from textbook
: would these pair of equations be parallel, perpendicular, or neither?
4x-3y=36;3x+4y=20?? how about ax-by=c;-ax+by=d?? This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
THE SLOPE OF EQUATION #1 IS
4X-3Y=36
-3Y=-4X+36
Y=-4X/-3+36
Y=4/3X+36 THEN THE SLOPE=4/3
THE SLOPE OF EQUATION # 2 IS
3X+4Y=20
4Y=-3X+20
Y=-3X/4+20
Y=-3/4X+20 THEN THE SLOPE=-3/4
THUS THESE 2 LINES ARE PERPENDICULAR BECAUSE THE SLOPES A NEGATIVE RECIPRICAL OF EACH OTHER.