SOLUTION: O.K., I took a stab at this one and got to a dead end - any help getting through it would be greatly appreciated!
A rectangular parking lot is 50ft. longer than it is wide. Det
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-> SOLUTION: O.K., I took a stab at this one and got to a dead end - any help getting through it would be greatly appreciated!
A rectangular parking lot is 50ft. longer than it is wide. Det
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Question 59264: O.K., I took a stab at this one and got to a dead end - any help getting through it would be greatly appreciated!
A rectangular parking lot is 50ft. longer than it is wide. Determine the dimentions of the parking lot if it measures 250ft. diagonally.
Thank you! Found 2 solutions by josmiceli, Cintchr:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The therorem of Pythagoras says
let x = h
x+50 = w
d = 250
complete the square
so, h = 150 ft and w = 200 ft
check to see if the diagonal is 250 ft
another check is, divide each dimension by 50
It's a 3-4-5 right triangle!
You can put this solution on YOUR website! For this you need the Pythagorean Theorum.
a = length (altitude) = b+50
b = width (base) = b
c - diagonal (hypotenuse) = 250
Foil the binomial
combine like terms
Square the Hypotenuse
Move all values to the left side
Divide all parts by 2
Factor
set each piece equal to 0 and and
a Distance CAN NOT be a negative value.
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