SOLUTION: Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -
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Linear-equations
-> SOLUTION: Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -
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Question 585123: Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -3x
2y=-3x+8
then i divided 2y by 2 and -3x+8 by 2
y=-3/2x+4
then i need to find the x inter or b in y=mx+b
I plug in the coordinates from the equation, (6,-2)
-2=-3/2x(6/1)+b
-2=-18/2+b
-2=-9+b
+9 +9
7=b
The line perpendicular to y=-3/2x+4 is y=-3/2x+7?
The answer i found is y=-3/2x+7
Now I'm not sure if this answer is correct...
Thank you for your help.
You can put this solution on YOUR website! Can you please help me solve this problem, thank you.
The equation of the line perpendicular to 3x+2y=8 and containing (6,-2) is:
Formula: y=mx+b
3x+2y=8
-3x -3x
2y=-3x+8
then i divided 2y by 2 and -3x+8 by 2
y=-3/2x+4
Right here you have to determine the slope of the perpendicular line
the relationship of slopes of perpendicular lines: m1*m2 = -1
m1 =
m2 = slope of perpendicular line *m2 = -1
m2 = -1 *
m2 = the slope of the perpendicular line
:
Use the point/slope form to find the equation: y - y1 = m(x - x1)
m =
x1 = 6
y2 = -2
y - (-2) = (x - 6)
y + 2 = x - 4
y = x - 4 - 2
y = x - 6; the equation of the perpendicular line
:
Graphically
