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Question 584611: -3y+6x= -18 what are the intercepts
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! To find the x-intercept, put 0 in for y
-3y + 6x = -18
-3(0) + 6x = -18 {substituted 0 in for y}
6x = -18 {multiplied -3 by 0}
x = -3 {divided both sides by 6}
x-intercept is -3
coordinates are (-3,0)
To find they-intercept, put 0 in for x
-3y + 6x = -18
-3y + 6(0) = -18 {substituted 0 in for x}
-3y = -18 {multiplied 6 by 0}
y = 6 {divided both sides by -3}
y-intercept is 6
coordinates are (0,6)
For more help from me, visit: www.algebrahouse.com
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