SOLUTION: Find the equation of the line with slope -1 that is the tangent to the curve y=1/x-1
I'm pretty sure this involves rearranging this into a quadratic equation then using the disc
Algebra ->
Linear-equations
-> SOLUTION: Find the equation of the line with slope -1 that is the tangent to the curve y=1/x-1
I'm pretty sure this involves rearranging this into a quadratic equation then using the disc
Log On
Question 576496: Find the equation of the line with slope -1 that is the tangent to the curve y=1/x-1
I'm pretty sure this involves rearranging this into a quadratic equation then using the discriminant (b^2-4ac) of the quadratic formula to find "k" in y=mx+k. Answer by richard1234(7193) (Show Source):
In either case, quadratics or discriminants won't help. Take dy/dx of both sides:
, or
depending on whether you intend (1/x)-1 or 1/(x-1). Set dy/dx = -1, solve for x, find the equation of the tangent line using point-slope form (since you have the slope and you can find a point on the graph).
