SOLUTION: I need help solving this word problem...I have been trying for 2 hours.
In 1920, the record for a certain race was 45.4 sec. In 1970, it was 44.4 sec.
Let R(t)=the record in
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-> SOLUTION: I need help solving this word problem...I have been trying for 2 hours.
In 1920, the record for a certain race was 45.4 sec. In 1970, it was 44.4 sec.
Let R(t)=the record in
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Question 571138: I need help solving this word problem...I have been trying for 2 hours.
In 1920, the record for a certain race was 45.4 sec. In 1970, it was 44.4 sec.
Let R(t)=the record in the race and t=the number of years since 1920.
Find a linear function that fits the data
R(t)=
Round to nearest hundredth
What is the predicted record for 2003____sec
What is the predicted record for 2006?
In what year will the predicted record be 43.50 seconds?
Thanks so much! Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! year Record time
1920 45.4 seconds
1970 44.4 seconds
Difference
50 -1
rate of reduction per year =-1 /50 = -0.02
R(t)= 45.4-0.020t
2003 t=83
R(t)= 45.4 + -0.020 * 83
R (83)= 43.74 seconds
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R(t)= 45.4-0.02t
43.5=45.4-0.02t
45.4-43.5=0.02t
1.9=0.02t
t= 1.9/0.02
t=95 years
1920 +95 = 2015
year 2015 it will bve 43.5 seconds
