SOLUTION: I am using the intercept method and I do not know the beginning this is the problem and this is what I got 2x+3y=6 3x=6-2x subtract 6-2 add from there I am lost please help me

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Question 56784: I am using the intercept method and I do not know the beginning this is the problem and this is what I got
2x+3y=6
3x=6-2x subtract
6-2 add from there I am lost please help me get the concept Thank you
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
2x+3y=6
3y=-2x+6
Divide thru by 3 to get:
y = (-2/3)x+(6/3)
y= (-2/3)x+2
Cheers,
Stan H

Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website!
I am using the intercept method:
2x+3y=6
Let x=0 and solve for y, this is the y-intecept:
2(0)+3y=6
0+3y=6
3y=6
3y/3=6/3
y=2
Plot the y-intercept: (0,2)
Let y=0 and solve for x, this is the x-intercept:
2x+3(0)=6
2x+0=6
2x=6
2x/2=6/2
x=3
Plot the x-intercept: (3,0)
Connect the dots and you should have a line that looks like:

Happy Calculating!!!