SOLUTION: write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2

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Question 565612: write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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write an equation that has an x intercept of 3 and is perpendicular to the graph of 5x-3y=2
:
Put the equation in the slope/intercept form to find the slope (y = mx + b)
5x - 3y = 2
- 3y = -5x + 2
Multiply both sides by -1
3y = 5x - 2
divide both sides by 3
y = 5%2F3x - 2%2F3
Slope m1 = 5%2F3
:
The relationship of slope in perpendicular lines is: m1*m2 = -1
Find m2
5%2F3*m2 = -1
m2 = -3%2F5 is the slope of the perpendicular line
:
y = -3%2F5x + b
The x intercept occurs when y = 0, find b
-3%2F5*3 + b = 0
-9%2F5 + b = 0
b = 9%2F5
therefore
y - -3%2F5x + 9%2F5 is the equation of the perpendicular line with an x intercept of 3.
:
Graphically