SOLUTION: I would greatly appreciate any help I could get with this problem. I have tried working it out several time and cannot seem to get it right. Solve the equations for the solution

Algebra ->  Linear-equations -> SOLUTION: I would greatly appreciate any help I could get with this problem. I have tried working it out several time and cannot seem to get it right. Solve the equations for the solution      Log On


   



Question 560042: I would greatly appreciate any help I could get with this problem. I have tried working it out several time and cannot seem to get it right.
Solve the equations for the solutions, x and y.
x - y = 0
6x + 5y = -22

Found 2 solutions by Maths68, josmiceli:
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
x-y=0........(1)
6x+5y=-22....(2)
Take (1)
x-y=0
x=y.......(3)
Put the value of x in (2)
6x+5y=-22....(2)
6y+5y=-22
11y=-22
11y/11=-22/11
y=-2
Put the value of x in (3)
x=y
x=-2
x,y=-2,-2


Check
======
Put the value of x and y in (1)
x-y=0
-2-(-2)=0
-2+2=0
0=0
Put the value of x and y in (2)
6x+5y=-22....(2)
6(-2)+5(-2)-22
-12-10=-22
-22=-22

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) x+-+y+=+0+
(2) 6x+%2B+5y+=+-22+
If it doesn't matter what method to use,
the easiest way is by substitution
-------------
Add y to both sides of (1)
(1) +x+=+y+
Now where I see x in equation (2),
I can substitute y
(2) +6y+%2B+5y+=+-22+
(2) +11y+=+-22+
(2) +y+=+-2+
Now if I plug this value of y
back into (1), I get
(1) +x+-+%28-2%29+=+0+
(1) +x+%2B+2+=+0+
Subtract 2 from both sides
(1) +x+=+-2+
So, the solution is (-2,-2)
Here's a plot of the equations that shows this:
+graph%28+400%2C+400%2C+-6%2C+6%2C+-6%2C+6%2C+x%2C+%28-6%2F5%29%2Ax+-+22%2F5+%29+