SOLUTION: Line two is perpendicular to 3x-12y=24 and passes through the point (2,-5). Find an equation for line two. (Use the slope of line two). I have worked this problem by finding

Algebra ->  Linear-equations -> SOLUTION: Line two is perpendicular to 3x-12y=24 and passes through the point (2,-5). Find an equation for line two. (Use the slope of line two). I have worked this problem by finding      Log On


   

Question 559201: Line two is perpendicular to 3x-12y=24 and passes through the point (2,-5). Find an equation for line two. (Use the slope of line two).

I have worked this problem by finding the slope of 3x-12y=24, which is 1/4. Also, the perpendicular line (line two) has a slope of -4. I am just a little stumped on how to Find an equation that passes through the point (2,-5). Please help.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
ONE WAY
You could do it by writing the equation of the line in point-slope form, using the coordinates of the point given:
y-%28-5%29=-4%28x-2%29
and then you could work with it to transform it into an equivalent expression that looks more elegant, like this:
y-%28-5%29=-4%28x-2%29 --> y%2B5=-4x%2B8 --> y=-4x%2B8-5 --> y=-4x%2B3
or y-%28-5%29=-4%28x-2%29 --> y%2B5=-4x%2B8 --> 4x%2By%2B5=8 --> 4x%2By=3
ANOTHER WAY
You could also write the slope-intercept form of a line with slope -4 as
y=-4x%2Bb and find b by substituting the coordinates of the point and solving for b
-5=-4%2A2%2Bb --> -5=-8%2Bb --> -5%2B8=b --> b=3
So you get y=-4x%2B3.