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Question 552013: Write an equation of the line that passes through the given point and is perpendicular to the given line.
problem 1.
(1,-1),y=3x+2
problem 2.
(5,0),y=2/3x-4
problem 3.
(3,-7),y=-1/5x+1
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! 1 y = 3 x + 2
Divide by 1
y = 3.000 x + 2
Compare this equation with y=mx+b
slope m = 3
The slope of a line perpendicular to the above line will be the negative reciprocal m1*m2=-1
The slope of the required line will be -1/3
m= - 1/3 ,point ( 1 , -1 )
Find b by plugging the values of m & the point in
y=mx+b
-1 = -1/3 + b
b= -2/3
m= - 1/3
The required equation is y = - 1/ 3 x - 2/ 3
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1 y = 2/3 x -4
Divide by 1
y = 0.667 x + -4
Compare this equation with y=mx+b
slope m = 2/3
The slope of a line perpendicular to the above line will be the negative reciprocal -1.5
m1*m2=-1
m= -3/2 ,point ( 5 , 0 )
Find b by plugging the values of m & the point in
y=mx+b
0 = -15/2 + b
b= 15/2
m= -3/2
The required equation is y = -3/ 2 x + 15/ 2
m.ananth@hotmail.ca
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