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Question 545128: Find the slope of a line perpendicular to a line passing through (5,6) and (-9,10)
Answer by saifoo.khan(162)   (Show Source):
You can put this solution on YOUR website! Slope of this line = (y2-y1)/(x2-x1)
(5,6) and (-9,10)
(10-6)/(-9-5)
4/-14
-2/7
The slope of this current line is -2/7
now to find the slope of the perp line, this formula is used
m1 * m2 = -1
slope of first line times slope of perpendicular = -1
so,
-2/7 * m2 = -1
2/7 * m2 = 1
m2 = 7/2
So now u have the slope of it's perpendicular line,
Hope u got the answer required.
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