SOLUTION: Please help me solve this equation: {{{y=13x-1}}} {{{y=10x+29}}} I can figure it out when I have to solve for an x when the y is given but don't understand when there is two y'

Algebra ->  Linear-equations -> SOLUTION: Please help me solve this equation: {{{y=13x-1}}} {{{y=10x+29}}} I can figure it out when I have to solve for an x when the y is given but don't understand when there is two y'      Log On


   

Question 544516: Please help me solve this equation: y=13x-1
y=10x%2B29
I can figure it out when I have to solve for an x when the y is given but don't understand when there is two y's. Please help and thanks!
Found 2 solutions by mananth, lwsshak3:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
y=13x-1
y=10x%2B29
Since both are equal to y
equate the two
13x-1=10x%2B29
-10x
13x-10x-1=10x-10x+29
3x-1=29
+1
3x=30
x=10
plugt x
in y y=13%2A10-1
y=129



Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation:
y=13x-1
y=10x+29
What you have here is a system of two straight line equations.
To solve, you must end up with an equation with only one variable.
To do this you can substitute x in terms of y or vise=versa, or use the elimination method.
In this case the easiest thing to do is equate the right side of both equations to each other since they are both=y.
..
13x-1=10x+29
3x=30
x=10
y=13x-1=13*10-1
y=130-1=129
This means the two lines intersect at (10,129)