SOLUTION: (-4,0) slope 5/2
y-0= 5/2(x--4)
y-0 = 5/2x-15
+0 +0
y= 5/2- -10
Is this how to solve this problem... If not could you please show me how and what exactly I did wrong
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-> SOLUTION: (-4,0) slope 5/2
y-0= 5/2(x--4)
y-0 = 5/2x-15
+0 +0
y= 5/2- -10
Is this how to solve this problem... If not could you please show me how and what exactly I did wrong
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Question 53751This question is from textbook Beginning Algebra
: (-4,0) slope 5/2
y-0= 5/2(x--4)
y-0 = 5/2x-15
+0 +0
y= 5/2- -10
Is this how to solve this problem... If not could you please show me how and what exactly I did wrong.. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! (-4,0) slope 5/2
y-0= 5/2(x--4)
Mistake here: --4 is +4, so you should have the following:
y-0 = 5/2x+10
y= (5/2)x+10
Cheers,
Stan H.
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