SOLUTION: an equation that goes through the point (1, 5) and has a slope of 2/3
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Question 537259
:
an equation that goes through the point (1, 5) and has a slope of 2/3
Answer by
jim_thompson5910(35256)
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y-y1 = m(x-x1)
y-5=(2/3)(x-1)
y-5=(2/3)x-(2/3)(1)
y-5=(2/3)x-2/3
y=(2/3)x-2/3+5
y=(2/3)x+13/3
So the answer is
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