SOLUTION: If the equation of a line is y=4/3x+8 what is the equation of a line six away and parallel to the first line? It has to do something with being six away based off the length of the

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Question 532836: If the equation of a line is y=4/3x+8 what is the equation of a line six away and parallel to the first line? It has to do something with being six away based off the length of the perpendicular.
Answer by lwsshak3(11628) (Show Source):
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If the equation of a line is y=4/3x+8 what is the equation of a line six away and parallel to the first line? It has to do something with being six away based off the length of the perpendicular.
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y=4/3x+8
The problem is to determine how much to drop given equation so that the perpendicular distance from a parallel line is 6 units.
let x=distance y must be dropped
You can work with a right triangle in which this perpendicular distance is the opposite side of a right triangle whose tan of the opposite angle is 3/4, the slope of given straight line equation.
The sin of this angle is equal to 3/5.
sin of angle=3/5=6/x
x=10
Given equation should be dropped vertically 10 units
Ans:
Equation of a line six away and parallel to the first line: y=4x/3-2