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Question 523225: Could you please show me how to graph this problem?
y=1/3x-4 and 3y-x=4
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Could you please show me how to graph this problem?
y=1/3x-4 and 3y-x=4
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These two equations are of straight lines of standard form: y=
+b, m=slope, b=y-intercept.
To graph these lines, equations should be in standard form.
The first equation, y=(1/3)x-4 is already in standard form.
Changing second equation into standard form:
3y-x=4
3y=x+4
y=x/3+4
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Only two points are needed to graph the line
For first equation, the y-intercept=-4, so you have one point at (0,-4)
To find the second point, use the slope=1/3=rise/run=∆y/∆x
From the y-intercept (0,-4) move up one unit and 3 units to the right which gives you the second point at (3,-3). The graph of the line go thru these two points (0,-4)
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Graphing the line of the second equation is with the same slope but the y-intercept is 4 instead of
-4. You should end up with two lines parallel to each other with slopes of 1/3
see the graph below as a visual check on your graphs
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