SOLUTION: write an equation of a slope-intercept form for the line pass through (8,6),perpendicular to 2x-y=4

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Question 519625: write an equation of a slope-intercept form for the line pass through (8,6),perpendicular to 2x-y=4
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
The reference equation is:
2x -y = 4
-y = -2x + 4
y = 2x -4
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y-intercept = (0, -4)
x-intercept = (2, 0)
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The line perpendicular to it will have a slope = inverse reciprocal of 2, which is -1/2.
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y = -1/2x +b
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Use a known point to find 'b'.
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6 = -1/2*(8) +b
6 = -4 + b
b = 10
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y = -1/2x + 10
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y-intercept = (0,10)
x-intercept = (20,0)
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In the following graph y=2x-4 is red and y=-1/2x+10 is green.
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+graph%28500%2C500%2C-25%2C25%2C-25%2C25%2C2%2Ax-4%2C-1%2F2%2Ax%2B10%29+