SOLUTION: what is the standard form of perpendicular to y=13, through (-2,5)

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Question 512036: what is the standard form of perpendicular to y=13, through (-2,5)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+13+ is a horizontal line where there are many
values of x, but at every point on the line, +y+=+13+
Any line perpendicular to this line must be a vertical line
If the line passes through (-2,5), then the equation
of this line must be +x+=+-2+