SOLUTION: solve the problem:
The worlds largest taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of these two ingredients was 617.6 kg. To th
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The worlds largest taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of these two ingredients was 617.6 kg. To th
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Question 509540: solve the problem:
The worlds largest taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of these two ingredients was 617.6 kg. To the nearest tenth of a kilogram, how many kilograms of each ingredient were used to make the taco?
I am struggling with turning the story problem into the actual equation.
You can put this solution on YOUR website! The ratio of onions to grilled steak was 1:6.6 kg.
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In this case, 'k' is simply an constant multiplier.
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1k + 6.6k = 617.6
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7.6k = 617.6
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k = 617.6/7.6
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k = 81.3
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So the taco contained about 81.3 kg of onions and 6.6*81.3 = 536.3 kg of grilled steak.
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Done.
You can put this solution on YOUR website! The worlds largest taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of these two ingredients was 617.6 kg. To the nearest tenth of a kilogram, how many kilograms of each ingredient were used to make the taco?
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1 kg of onion for every 6.6 kg of grilled steak is
a ratio of 1:6.6
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1:6.6 is the same as x:6.6x where x is the onion weight.
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Equation:
x + 6.6x = 617.6
7.6x = 617.6
x = 81.26 kg (amount of onion in the taco)
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6.6x = 6.6*81.26 = 536.32 kg (amount of grilled steak in the taco)
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Cheers,
Stan H.
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