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Question 509313: write an equation of the line that passes through point (4,7) and is perpendicular to the line whose equation is 2x+3y=4
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! write an equation of the line that passes through point (4,7) and is perpendicular to the line whose equation is 2x+3y=4
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slope-intercept form of the given line: y = (-2/3)x +(4/3)
Notice the slope is -2/3
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Any perpendicular line must have slope = 3/2
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Find equation of line with m = 3/2 passing thru (4,7)
Form: y = mx + b
7 = (3/2)4 + b
7 = 6 + b
b = 1
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Equation:
y = (3/2)x + 1
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Cheers,
Stan H.
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