SOLUTION: Find the equation of the line in slope-intercept form that goes through the points (1,28) and (3,40).

Algebra ->  Linear-equations -> SOLUTION: Find the equation of the line in slope-intercept form that goes through the points (1,28) and (3,40).      Log On


   

Question 509035: Find the equation of the line in slope-intercept form that goes through the points (1,28) and (3,40).
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Note: is the first point . So this means that x%5B1%5D=1 and y%5B1%5D=28.
Also, is the second point . So this means that x%5B2%5D=3 and y%5B2%5D=40.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%2840-28%29%2F%283-1%29 Plug in y%5B2%5D=40, y%5B1%5D=28, x%5B2%5D=3, and x%5B1%5D=1


m=%2812%29%2F%283-1%29 Subtract 28 from 40 to get 12


m=%2812%29%2F%282%29 Subtract 1 from 3 to get 2


m=6 Reduce


So the slope of the line that goes through the points and is m=6