SOLUTION: How would I graph the line described (-4,-6);m=6? I tried doing the y=mx+b but it really doesn't make sense on this question.

Algebra ->  Linear-equations -> SOLUTION: How would I graph the line described (-4,-6);m=6? I tried doing the y=mx+b but it really doesn't make sense on this question.      Log On


   



Question 491566: How would I graph the line described (-4,-6);m=6? I tried doing the y=mx+b but it really doesn't make sense on this question.
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
y = mx + b
m = 6
y = 6x + b
.
You know the line goes through (-4,-6), which means,
x = -4
y = -6
.
-6 = 6*(-4) + b
-6 = -24 + b
b = 18
.
y = 6x + 18
.
graph%28500%2C500%2C-30%2C30%2C-30%2C30%2C+6%2Ax%2B18%29