SOLUTION: If each engineer needs to meet with each other individually, how many engineers would equal 66 meetings? I cannot come up with this number in my son's homework question. I get 8 e
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Question 491489: If each engineer needs to meet with each other individually, how many engineers would equal 66 meetings? I cannot come up with this number in my son's homework question. I get 8 engineers at 56 meetings, or 9 engineers at 72 meetings. Please help! Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! We want nC2 = 66 because the number of ways to choose two engineers to meet out of a pool of n is 66. Hence,
