SOLUTION: How do I find intercepts for the graph of the equation given: x+6y=0

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Question 486885: How do I find intercepts for the graph of the equation given:
x+6y=0

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the y intercept is the value of y when x is equal to 0.
the x intercept is the value of x when y is equal to 0.

your equation is x + 6y = 0

when x is equal to 0, the value of y is equal to 0.
when y is equal to 0, the value of x is equal to 0.
your x and y intercepts are both equal to 0.

the graph of the equation goes through the origin.

here's what your graph looks like.

graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C-x%2F6%29

to graph this equation, you needed to solve for y.

you start with x + 6y = 0
subtract x from both sides of the equation to get 6y = -x
divide both sides of the equation by 6 to get y = -x/6

when you solved for y, you converted the equation from standard form of ax + by = c to slope intercept form of y = mx + b.

m is the slope and b is the y intercept.

your slope is -(1/6)
your y intercept is 0.

to find the x intercept when the equation is in this form, simply set y = 0 and solve for x.

y = -(1/6)x becomes 0 = -(1/6)x.
divide both sides of this equation by -(1/6) to get 0 = x.

you wind up with the same answer regardless of the form the equation is in to start with.

x intercept = 0
t intercept = 0