SOLUTION: Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2

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Question 486515: Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2
Found 2 solutions by lwsshak3, Gogonati:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2
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Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
For given equation of line:
-7x+9y=-2
9y=7x-2
y=7x/9-2/9
slope m=7/9
..
slope of line perpendicular to given line=-9/7 (negative reciprocal)
Equation: y=(-9/7)x+b
solving for b using given point (-7,6)
6=(-9/7)*7+b
6=-9+b
b=16
Equation of perpendicular line:
y=-9x/7+16

Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
We write the equation -7x+9y=-2 in the slope intercept form y=%287%2F9%29%2Ax-2%2F9
As we know perpendicular lines have reciprocal negatives slopes.
Therefore we must find the equation of a line with slope -9/7 through the point
(-7, 6). This equation is given by the formula y-y%5B0%5D=m%28x-x%5B0%5D%29,
substituting we get: y-6=%28-9%2F7%29%28x%2B7%29. Simplifying this equation we get:
y=%28-9%2F7%29x-3, what is the required equation.