SOLUTION: trying to answer this question and the program keeps saying i am wrong. not sure where i am messing up. It wants me to answer in standard form and gives me a point of (3,1) with a

Algebra ->  Linear-equations -> SOLUTION: trying to answer this question and the program keeps saying i am wrong. not sure where i am messing up. It wants me to answer in standard form and gives me a point of (3,1) with a      Log On


   

Question 480815: trying to answer this question and the program keeps saying i am wrong. not sure where i am messing up.
It wants me to answer in standard form and gives me a point of (3,1) with a slope of 2/5. sorry for being so vague.
Found 2 solutions by Tatiana_Stebko, mathstutor494:
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
y-y%5B1%5D=m%28x-x%5B1%5D%29
point (3,1) x%5B1%5D=3, y%5B1%5D=1, a slope m=2%2F5
y-1=%282%2F5%29%28x-3%29multiply by 5
5%28y-1%29=2%28x-3%29
5y-5=2x-6
5y-5-2x%2B6=0
-2x%2B5y%2B1=0 multiply by (-1)
2x-5y-1=0 the standard form

Answer by mathstutor494(120) About Me  (Show Source):
You can put this solution on YOUR website!
I think you need to use Point-slope form to answer this question which states that equation of a line through the points (x1, y1) and slope m is given by
y-y1 = m (x-x1)
Here you are given m & (x1,y1) in the question, so substituting values in the above formulae..
y-1 = (2/5) (x-3)
Multiplying both sides by 5 results in
5(y-1) = 2(x-3)
Further simplification leads to
5y-5=2x-6
5y = 2x-6+5
5y = 2x-1
Dividing both sides by 5
y= 2x/5 -1/5