SOLUTION: In a town election with two candidates, the winning candidate had 220 more votes than the loser. If 810 votes were case in all, how many votes did each candidate receive?
Algebra ->
Linear-equations
-> SOLUTION: In a town election with two candidates, the winning candidate had 220 more votes than the loser. If 810 votes were case in all, how many votes did each candidate receive?
Log On
Question 47904: In a town election with two candidates, the winning candidate had 220 more votes than the loser. If 810 votes were case in all, how many votes did each candidate receive? Found 2 solutions by 1980.vikas, Bucket:Answer by 1980.vikas(7) (Show Source):
You can put this solution on YOUR website! Let the loser get x no. of votes, then the winner gets (x + 220) votes.
Now as the total no of votes is 810, then
=> x + (x + 220) = 810
=> 2x + 220 = 810
=> 2x = 590
=> x = 295
so the loser get 295 votes while the winner gets 515 votes.