SOLUTION: I need to write the equation of the line that passes trhough P(-3,6) and perpendicular to the graph of y=-2/3x-7.
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Question 467674: I need to write the equation of the line that passes trhough P(-3,6) and perpendicular to the graph of y=-2/3x-7. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I need to write the equation of the line that passes trhough P(-3,6) and perpendicular to the graph of y=-2/3x-7.
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The given line has slope = -2/3
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Any line perpendicular to it must have slope = 3/2
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Form: y = mx + b
6 = (3/2)(-3)+ b
b = 6+ 9/2
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b = 10.5
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Equation:
y = (3/2)x + (21/2)
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Cheers,
Stan H.
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