SOLUTION: Please help me with this algebra problem. find the x and y intercepts -2x + 5y = 15

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Question 467427: Please help me with this algebra problem. find the x and y intercepts -2x + 5y = 15
Found 2 solutions by jim_thompson5910, algebrahouse.com:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x-intercept


To find the x-intercept, plug in y=0 and solve for x


-2x+%2B+5y+=+15 Start with the given equation.


-2x+%2B+5%280%29+=+15 Plug in y=0.


-2x+%2B+0+=+15 Multiply 5 and 0 to get 0.


-2x=15 Simplify.


x=%2815%29%2F%28-2%29 Divide both sides by -2 to isolate x.


x=-15%2F2 Reduce.


So the x-intercept is .


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y-intercept


To find the y-intercept, plug in x=0 and solve for y


-2x+%2B+5y+=+15 Start with the given equation.


-2%280%29+%2B+5y+=+15 Plug in x=0.


-0+%2B+5y+=+15 Multiply -2 and 0 to get 0.


+%2B+5y+=+15 Simplify.


y=%2815%29%2F%285%29 Divide both sides by 5 to isolate y.


y=3 Reduce.


So the y-intercept is .


Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
-2x + 5y = 15

At the x-intercept (where the line crosses the x-axis), y is 0.
To find the x-intercept, substitute 0 in for y:
-2x + 5y = 15
-2x + 5(0) = 15 {substituted 0 in for y}
-2x = 15 {multiplied 5 by 0}
x = -15/2 {divided both sides by -2}
x-intercept is -15/2.....the coordinates are (-15/2,0)

At the y-intercept (where the line crosses the y-axis), x is 0.
To find the y-intercept, substitute 0 in for x}
-2x + 5y = 15
-2(0) + 5y = 15 {substituted 0 in for x}
5y = 15 {multiplied -2 by 0}
y = 3 {divided both sides by 5}
y-intercept is 3.....the coordinates are (0,3)

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