SOLUTION: find the equation of the line containing points ( 0, -3) and ( -12, -5)
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Question 462675
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find the equation of the line containing points ( 0, -3) and ( -12, -5)
Answer by
rfer(16322)
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m=(-5--3)/(-12-0)
m=-2/-12
m=1/6
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y=mx+b
-5=1/6*-12+b
-5=-2+b
-3=b
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y=1/6x-3