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Question 462143: Write the equation of a line that passes through (3, 5) and (6, -2).
Please and thanks!
Found 2 solutions by MathLover1, mananth:
Answer by MathLover1(20849)   (Show Source):
You can put this solution on YOUR website!
the equation of a line that passes through (3, 5) and (6, -2) is:
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (3, 5) and (x2, y2) = (6, -2).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(-2.33333333333333)x + (12)
Your graph:
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Answer by mananth(16946)  (Show Source):
You can put this solution on YOUR website! x1 y1 x2 y2
3 5 6 -2
slope m = (y2-y1)/(x2-x1)
( -2 - 5 )/( 6 - 3 )
( -7 / 3 )
m= -2.33
Plug value of the slope and point (3,5)in
Y = m x + b
5.00 = -7 + b
b= 5 -7
b= 12
So the equation will be
Y = -2.33 x + 12
m.ananth@hotmail.ca
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