SOLUTION: Find the equation of the line containing the point and perpendicular to the given line. (0,–7); 4x + 3 = y please show work.
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-> SOLUTION: Find the equation of the line containing the point and perpendicular to the given line. (0,–7); 4x + 3 = y please show work.
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Question 460132: Find the equation of the line containing the point and perpendicular to the given line. (0,–7); 4x + 3 = y please show work. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the equation of the line containing the point and perpendicular to the given line. (0,–7); 4x + 3 = y
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y = 4x + 3 is in slope-intercept form, so slope = 4
Lines perpendicular have a slope that's the negative inverse, m = -1/4
Use y = mx + b and the point to find b
-7 = m*0 + b
b = -7
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--> y = (-1/4)x - 7
x + 4y = -28
