SOLUTION: give the equation of the line perpindicular to 6x-3y=12 and whose y-int is -4

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Question 459543: give the equation of the line perpindicular to 6x-3y=12 and whose y-int is -4
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
6x-3y=12 and whose y-int is -4
6x-3y=12
3y=6x-12
y=2x-4
slope m = 2
the slope of perpendicular line will be -1/2.
y ntercept of the required line is -4
so the equation is
y=-1/2 x -4
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cy=%28-x%2F2-4%29%2Cy=2x-4%29%29