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Question 458213: Write an equation in standard form for the line described. through (7,9), perpendicular to 4x+y=7
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write an equation in standard form for the line described. through (7,9), perpendicular to 4x+y=7
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The slope of the given line is -4
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Any line that is perpendicular must have a slope of 1/4
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Find equation of line with slope = 1/4 where y = 9 when x = 7.
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Form: y = mx + b
Solve for "b":
9 = (1/4)7 + b
36/4 = 7/4 + b
b = 29/4
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y = (1/4)x + (29/4)
Cheers,
Stan H.
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Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Write an equation in standard form for the line described. through (7,9), perpendicular to 4x+y=7
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Standard form for a straight line: y=mx+b, m= slope, and b= y-intercept
For given line:
4x+y=7
y=-4x+7
slope=-4
slope of line perpendicular to this line is the negative reciprocal=-(-1/4)=1/4
for line thru (7,9)
y=x/4+b
plug in x & y from given point (7,9)
9=7/4+b
b=9-7/4=36/4-7/4=32/4=8
Equation:
y=x/4+8
See graph of the two lines below as a visual check on the answer:
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