SOLUTION: Given two points through which a line passes, write the equation of each line in slope-intercept form. (4,0) and (2,-5)

Algebra ->  Linear-equations -> SOLUTION: Given two points through which a line passes, write the equation of each line in slope-intercept form. (4,0) and (2,-5)      Log On


   



Question 445782: Given two points through which a line passes, write the equation of each line in slope-intercept form.
(4,0) and (2,-5)

Found 3 solutions by rfer, nerdybill, josmiceli:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
slope m=(-5-0)/(2-4)
m=-5/-2
m=5/2
--------------
y=mx+b
-5=5/2*2+b
-5=5+b
b=-10
---------------
y=5/2x-10

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
first, find the slope between:
(4,0) and (2,-5)
m = (y2-y1)/(x2-x1)
m = (-5-0)/(2-4)
m = -5/(-2)
m= 5/2
.
use the slope and one point (4,0) plug it into "point-slope" form:
y - y1 = m(x - x1)
y - 0 = (5/2)(x - 4)
y = (5/2)x - 10 (this is what they're looking for)



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(4,0) and (2,-5)
+%28+y+-+%28-5%29+%29+%2F+%28+x+-+2+%29++=+%28+0+-+%28-5%29+%29+%2F+%28+4+-+2+%29+
+%28+y+%2B+5+%29+%2F+%28+x+-+2+%29++=+5+%2F+2+
Multiply both sides by +2%2A%28x-2%29+
+2%2A%28+y+%2B+5+%29+=+5%2A%28+x+-+2+%29+
+2y+%2B+10+=+5x+-+10+
+2y+=+5x+-+20+
+y+=+%285%2F2%29%2Ax+-+10+
check answer:
(4,0)
+0+=+%285%2F2%29%2A4+-+10+
+0+=+10+-+10+
+0+=+0+
OK
(2,-5)
+y+=+%285%2F2%29%2Ax+-+10+
+-5+=+%285%2F2%29%2A2+-+10+
+-5+=+5+-+10+
+-5+=+-5+
OK