SOLUTION: Solve the following systems of equation 2x + y =11 3x + 4y =4

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Question 443123: Solve the following systems of equation 2x + y =11 3x + 4y =4
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
2x + y =11
3x + 4y =4
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+1%5Cy+=+11%2C%0D%0A++++3%5Cx+%2B+4%5Cy+=+4+%29%0D%0A++We'll use substitution. After moving 1*y to the right, we get:
2%2Ax+=+11+-+1%2Ay, or x+=+11%2F2+-+1%2Ay%2F2. Substitute that
into another equation:
3%2A%2811%2F2+-+1%2Ay%2F2%29+%2B+4%5Cy+=+4 and simplify: So, we know that y=-5. Since x+=+11%2F2+-+1%2Ay%2F2, x=8.

Answer: system%28+x=8%2C+y=-5+%29.