SOLUTION: Does the equation ( x-3)^2 + (y +4)2 = -6 have a graph that is a circle?

Algebra ->  Linear-equations -> SOLUTION: Does the equation ( x-3)^2 + (y +4)2 = -6 have a graph that is a circle?      Log On


   

Question 43917: Does the equation ( x-3)^2 + (y +4)2 = -6 have a graph that is a circle?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
No. The -6 represents the radius squared, and, being negative does not represent a real figure,