SOLUTION: How do I solve this problem, Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.

Algebra ->  Linear-equations -> SOLUTION: How do I solve this problem, Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.      Log On


   

Question 436946: How do I solve this problem,
Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Your line represented by y+=+mx%2Bb
the line that passes through the y-axis at 5
it means if x=0, y=5; and that means b=5
y+=+mx%2B5
To find the slope of this line perpendicular to 2x=3y%2B4, write it in sloe-intercept form first:
+2x=3y%2B4
+3y=2x-4
+y=%282%2F3%29x-4%2F3
the slope is 2/3, and you take the negative reciprocal of the slop of your given line, or -3/2
This gives you a general line of y+=+-%283%2F2%29x%2B5.
now, graph them both:

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C-%283%2F2%29x%2B5%2C+%282%2F3%29x-4%2F3%29+


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

line passing through the y-axis at 5 and perpendicular to the graph of 2x=3y+4

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept. 

 2x = 3y+4  OR y = (-2/3)x - 4/3  Slope m = (-2/3)

New Line: 

 y = (3/2)x + 5   |Slopes of perpendicular lines are negative reciprocals