SOLUTION: Write an equation of the given line containing the given point and perpendicular to the given line. (7,3);4x+7y=9 express in form y=mx+b so y=

Algebra ->  Linear-equations -> SOLUTION: Write an equation of the given line containing the given point and perpendicular to the given line. (7,3);4x+7y=9 express in form y=mx+b so y=      Log On


   

Question 436788: Write an equation of the given line containing the given point and perpendicular to the given line.
(7,3);4x+7y=9
express in form y=mx+b
so y=
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
First write the equation of the line in the slope-intercept form:
y=%28-4%2F7%29x%2B%289%2F7%29 the slope of this line is m1=-4/7
Second we find the slope of the line perpendicular to the line y=%28-4%2F7%29x%2B9%2F7
We know perpendicular lines have reciprocal negative slopes: m2=-1/m1, therefore
m2=7/4. Now we write the equation of the line through the point (7, 3) and
perpendicular to the line y=%28-4%2F7%29x%2B9%2F7:
y-3=%287%2F4%29%28x-7%29, write it in standard form: 4%28y-3%29=7%28x-7%29} =>
7x-4y=37.
Done.